Local Data Search
A total of 39 results found. Show Results on Map.
| Rank | Russian as First Ancestry Population Percentage ▼ | City / Population |
| 1. | 9.2% | Manchester, VT / 536 |
| 2. | 9.2% | Waterbury, VT / 2,158 |
| 3. | 6.0% | South Shaftsbury, VT / 649 |
| 4. | 5.8% | Newfane, VT / 148 |
| 5. | 5.3% | Wilder, VT / 1,529 |
| 6. | 5.0% | Poultney, VT / 1,802 |
| 7. | 4.9% | Johnson, VT / 1,420 |
| 8. | 4.9% | Saxtons River, VT / 391 |
| 9. | 4.0% | North Bennington, VT / 1,366 |
| 10. | 3.8% | Brattleboro, VT / 7,857 |
| 11. | 3.7% | Montpelier, VT / 7,792 |
| 12. | 3.3% | Woodstock, VT / 731 |
| 13. | 3.1% | Perkinsville, VT / 96 |
| 14. | 3.0% | Burlington, VT / 38,630 |
| 15. | 2.9% | West Brattleboro, VT / 3,272 |
| 16. | 2.9% | Middlebury, VT / 6,199 |
| 17. | 2.4% | South Burlington, VT / 17,208 |
| 18. | 2.2% | Springfield, VT / 3,282 |
| 19. | 2.0% | Enosburg Falls, VT / 1,567 |
| 20. | 1.8% | Old Bennington, VT / 205 |
| 21. | 1.6% | Lyndonville, VT / 1,167 |
| 22. | 1.3% | Cabot, VT / 272 |
| 23. | 1.2% | Arlington, VT / 1,230 |
| 24. | 1.0% | Wallingford, VT / 802 |
| 25. | 0.8% | Essex Junction, VT / 8,939 |
| 26. | 0.8% | Bellows Falls, VT / 3,364 |
| 27. | 0.6% | Winooski, VT / 6,278 |
| 28. | 0.6% | Bennington, VT / 8,691 |
| 29. | 0.6% | Barre, VT / 8,893 |
| 30. | 0.6% | Jericho, VT / 1,679 |
| 31. | 0.5% | Saint Johnsbury, VT / 6,816 |
| 32. | 0.5% | Newport, VT / 5,150 |
| 33. | 0.5% | Brandon, VT / 1,980 |
| 34. | 0.4% | Ludlow, VT / 1,079 |
| 35. | 0.4% | Saint Albans, VT / 7,311 |
| 36. | 0.3% | Northfield, VT / 3,117 |
| 37. | 0.3% | West Rutland, VT / 2,351 |
| 38. | 0.3% | Westminster, VT / 400 |
| 38. | 0.3% | Rutland, VT / 16,770 |
Please note that we only rank locations with 'Russian as First Ancestry Population Percentage' data. The rank above might not be a complete list. Locations without 'Russian as First Ancestry Population Percentage' data are not listed.
*ACS stands for U.S. Census American Community Survey. According to the U.S. Census, if the date is a range, you can interpret the data as an average of the period of time.