Local Data Search
A total of 40 results found. Show Results on Map.
| Rank | Danish as First Ancestry Population Percentage ▼ | City / Population |
| 1. | 11.6% | Greensboro Bend, VT / 223 |
| 2. | 6.3% | Milton, VT / 1,815 |
| 3. | 4.0% | Wilmington, VT / 568 |
| 4. | 3.0% | Norwich, VT / 1,020 |
| 5. | 2.4% | Barnet, VT / 157 |
| 6. | 2.3% | Shelburne, VT / 968 |
| 7. | 1.8% | Pittsford, VT / 575 |
| 8. | 1.6% | South Barre, VT / 1,404 |
| 9. | 1.4% | Derby Line, VT / 925 |
| 10. | 1.3% | Lyndonville, VT / 1,310 |
| 10. | 1.3% | Saxtons River, VT / 569 |
| 12. | 1.2% | Manchester, VT / 752 |
| 12. | 1.2% | Bradford, VT / 952 |
| 14. | 1.1% | Wells River, VT / 365 |
| 15. | 0.9% | Brattleboro, VT / 6,981 |
| 16. | 0.9% | Manchester Center, VT / 1,937 |
| 17. | 0.9% | Readsboro, VT / 266 |
| 18. | 0.9% | North Bennington, VT / 1,812 |
| 18. | 0.9% | Essex Junction, VT / 9,298 |
| 20. | 0.8% | Brandon, VT / 1,560 |
| 21. | 0.8% | Cabot, VT / 304 |
| 22. | 0.8% | Newport, VT / 4,601 |
| 23. | 0.8% | Arlington, VT / 1,302 |
| 24. | 0.7% | Perkinsville, VT / 143 |
| 25. | 0.6% | Winooski, VT / 7,223 |
| 26. | 0.6% | Woodstock, VT / 937 |
| 27. | 0.6% | Vergennes, VT / 2,594 |
| 28. | 0.5% | Hardwick, VT / 1,378 |
| 29. | 0.5% | Waterbury, VT / 2,094 |
| 30. | 0.4% | Burlington, VT / 42,259 |
| 31. | 0.4% | South Burlington, VT / 17,913 |
| 32. | 0.4% | Northfield, VT / 2,969 |
| 32. | 0.4% | Montpelier, VT / 7,847 |
| 34. | 0.4% | Middlebury, VT / 6,518 |
| 35. | 0.4% | Bellows Falls, VT / 2,825 |
| 36. | 0.3% | West Brattleboro, VT / 2,837 |
| 37. | 0.3% | Bennington, VT / 8,869 |
| 38. | 0.2% | Saint Albans, VT / 6,944 |
| 39. | 0.1% | Poultney, VT / 1,710 |
| 39. | 0.1% | Barre, VT / 9,044 |
Please note that we only rank locations with 'Danish as First Ancestry Population Percentage' data. The rank above might not be a complete list. Locations without 'Danish as First Ancestry Population Percentage' data are not listed.
*ACS stands for U.S. Census American Community Survey. According to the U.S. Census, if the date is a range, you can interpret the data as an average of the period of time.