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Midvale, UT Historical Place of Birth and Citizenship Data

 

ACS 2010-2014 data

Total population: 29,957

 Midvale, UT%UtahU.S.
Native25,41384.83%, see rank91.61%86.93%
Born in the State of Residence17,22057.48%, see rank62.05%58.73%
Born in Different State8,02026.77%, see rank28.57%26.78%
Born in Puerto Rico, U.S. Island Areas,
or Born Abroad to American Parent(s)
1730.58%, see rank0.99%1.42%
Foreign Born4,54415.17%, see rank8.39%13.07%
Foreign Born with U.S. Citizenship1,2294.10%, see rank2.96%5.99%
Foreign Born without U.S. Citizenship3,31511.07%, see rank5.42%7.09%
Born In Europe2950.98%, see rank0.89%1.53%
Born In Asia8792.93%, see rank1.62%3.82%
Born In Africa990.33%, see rank0.24%0.55%
Born In Oceania200.07%, see rank0.32%0.07%
Born In Latin America3,13510.46%, see rank5.02%6.83%
Born In Northern America1160.39%, see rank0.29%0.26%

ACS 2008-2012 data

Total population: 28,484

 Midvale, UT%UtahU.S.
Native24,39585.64%, see rank91.73%87.13%
Born in the State of Residence16,21056.91%, see rank61.94%58.71%
Born in Different State7,95527.93%, see rank28.80%27.04%
Born in Puerto Rico, U.S. Island Areas,
or Born Abroad to American Parent(s)
2300.81%, see rank0.99%1.38%
Foreign Born4,08914.36%, see rank8.27%12.87%
Foreign Born with U.S. Citizenship9363.29%, see rank2.77%5.71%
Foreign Born without U.S. Citizenship3,15311.07%, see rank5.50%7.16%
Born In Europe3001.05%, see rank0.90%1.56%
Born In Asia5621.97%, see rank1.48%3.67%
Born In Africa00.00%, see rank0.22%0.51%
Born In Oceania240.08%, see rank0.32%0.07%
Born In Latin America3,14411.04%, see rank5.05%6.79%
Born In Northern America590.21%, see rank0.30%0.26%

ACS 2006-2010 data

Total population: 27,609

 Midvale, UT%UtahU.S.
Native23,42584.85%, see rank91.79%87.28%
Born in the State of Residence16,36059.26%, see rank62.34%58.66%
Born in Different State6,84724.80%, see rank28.43%27.28%
Born in Puerto Rico, U.S. Island Areas,
or Born Abroad to American Parent(s)
2180.79%, see rank1.02%1.33%
Foreign Born4,18415.15%, see rank8.21%12.72%
Foreign Born with U.S. Citizenship1,0923.96%, see rank2.67%5.48%
Foreign Born without U.S. Citizenship3,09211.20%, see rank5.54%7.24%
Born In Europe3551.29%, see rank0.91%1.59%
Born In Asia3401.23%, see rank1.41%3.54%
Born In Africa00.00%, see rank0.22%0.48%
Born In Oceania540.20%, see rank0.30%0.07%
Born In Latin America3,34712.12%, see rank5.07%6.77%
Born In Northern America880.32%, see rank0.30%0.27%

ACS 2005-2009 data

Total population: 27,799

 Midvale, UT%UtahU.S.
Native23,52684.63%, see rank92.08%87.61%
Born in the State of Residence15,48255.69%, see rank62.54%58.98%
Born in Different State7,79128.03%, see rank28.59%27.35%
Born in Puerto Rico, U.S. Island Areas,
or Born Abroad to American Parent(s)
2530.91%, see rank0.94%1.29%
Foreign Born4,27315.37%, see rank7.92%12.39%
Foreign Born with U.S. Citizenship1,0883.91%, see rank2.56%5.28%
Foreign Born without U.S. Citizenship3,18511.46%, see rank5.36%7.11%
Born In Europe3391.22%, see rank0.93%1.64%
Born In Asia2610.94%, see rank1.38%3.34%
Born In Africa00.00%, see rank0.18%0.46%
Born In Oceania440.16%, see rank0.31%0.07%
Born In Latin America3,54212.74%, see rank4.81%6.60%
Born In Northern America870.31%, see rank0.31%0.28%

US Census 2000 data

Total population: 27,029

 Midvale, UT%UtahU.S.
Native22,92684.82%, see rank92.90%88.95%
Born in the State of Residence15,64557.88%, see rank62.92%59.96%
Born in Different State7,11826.33%, see rank29.08%27.74%
Born in Puerto Rico, U.S. Island Areas,
or Born Abroad to American Parent(s)
1630.60%, see rank0.89%1.25%
Foreign Born4,11315.22%, see rank7.10%11.05%
Foreign Born with U.S. Citizenship6572.43%, see rank2.16%4.46%
Foreign Born without U.S. Citizenship3,45612.79%, see rank4.95%6.60%
Born In Europe3641.35%, see rank1.15%1.75%
Born In Asia4341.61%, see rank1.27%2.92%
Born In Africa390.14%, see rank0.11%0.31%
Born In Oceania620.23%, see rank0.30%0.06%
Born In Latin America3,10211.48%, see rank3.94%5.72%
Born In Northern America1120.41%, see rank0.35%0.29%

* ACS stands for U.S. Census American Community Survey. According to the U.S. Census, if the date is a range, you can interpret the data as an average of the period of time.


 
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