USA.com / Florida / Miami-Dade County / Kendall, FL / Population and Races / Historical Marital Status Data
Kendall, FL Historical Marital Status Data
ACS 2010-2014 data
Total population: 78,580
Kendall, FL | % | Florida | U.S. | |
15 Years and Over Total | 65,983 | see rank | 16,048,765 | 252,974,135 |
Males, 15 Years and Over | 31,965 | 100%, see rank | 7,772,434 | 123,281,364 |
Never Married | 11,582 | 36.23%, see rank | 34.62% | 35.77% |
Married | 16,109 | 50.40%, see rank | 50.83% | 52.04% |
Widowed | 949 | 2.97%, see rank | 3.18% | 2.57% |
Divorced | 3,325 | 10.40%, see rank | 11.37% | 9.62% |
Females, 15 Years and Over | 34,018 | 100%, see rank | 8,276,331 | 129,692,771 |
Never Married | 9,087 | 26.71%, see rank | 27.39% | 29.48% |
Married | 16,075 | 47.25%, see rank | 47.36% | 49.19% |
Widowed | 3,730 | 10.96%, see rank | 10.81% | 9.16% |
Divorced | 5,126 | 15.07%, see rank | 14.45% | 12.16% |
ACS 2008-2012 data
Total population: 77,462
Kendall, FL | % | Florida | U.S. | |
15 Years and Over Total | 64,785 | see rank | 15,597,732 | 248,042,237 |
Males, 15 Years and Over | 30,347 | 100%, see rank | 7,553,366 | 120,789,875 |
Never Married | 10,441 | 34.41%, see rank | 33.80% | 35.08% |
Married | 16,076 | 52.97%, see rank | 51.90% | 52.93% |
Widowed | 854 | 2.81%, see rank | 3.11% | 2.53% |
Divorced | 2,976 | 9.81%, see rank | 11.19% | 9.46% |
Females, 15 Years and Over | 34,438 | 100%, see rank | 8,044,366 | 127,252,362 |
Never Married | 9,138 | 26.53%, see rank | 26.43% | 28.74% |
Married | 15,993 | 46.44%, see rank | 48.48% | 49.95% |
Widowed | 4,018 | 11.67%, see rank | 10.89% | 9.34% |
Divorced | 5,289 | 15.36%, see rank | 14.21% | 11.97% |
ACS 2006-2010 data
Total population: 76,662
Kendall, FL | % | Florida | U.S. | |
15 Years and Over Total | 63,904 | see rank | 15,229,204 | 243,073,468 |
Males, 15 Years and Over | 29,137 | 100%, see rank | 7,372,839 | 118,264,295 |
Never Married | 10,117 | 34.72%, see rank | 32.51% | 34.21% |
Married | 15,608 | 53.57%, see rank | 53.51% | 54.02% |
Widowed | 846 | 2.90%, see rank | 3.07% | 2.52% |
Divorced | 2,566 | 8.81%, see rank | 10.91% | 9.25% |
Females, 15 Years and Over | 34,767 | 100%, see rank | 7,856,365 | 124,809,173 |
Never Married | 8,699 | 25.02%, see rank | 25.23% | 27.93% |
Married | 16,463 | 47.35%, see rank | 50.03% | 50.85% |
Widowed | 4,213 | 12.12%, see rank | 10.99% | 9.55% |
Divorced | 5,392 | 15.51%, see rank | 13.75% | 11.66% |
ACS 2005-2009 data
Total population: 82,388
Kendall, FL | % | Florida | U.S. | |
15 Years and Over Total | 67,203 | see rank | 14,879,114 | 240,146,935 |
Males, 15 Years and Over | 30,868 | 100%, see rank | 7,241,020 | 117,166,601 |
Never Married | 10,626 | 34.42%, see rank | 32.10% | 34.13% |
Married | 16,669 | 54.00%, see rank | 54.11% | 54.15% |
Widowed | 1,020 | 3.30%, see rank | 3.11% | 2.53% |
Divorced | 2,553 | 8.27%, see rank | 10.68% | 9.19% |
Females, 15 Years and Over | 36,335 | 100%, see rank | 7,638,094 | 122,980,334 |
Never Married | 9,049 | 24.90%, see rank | 24.60% | 27.67% |
Married | 17,325 | 47.68%, see rank | 50.51% | 50.88% |
Widowed | 4,412 | 12.14%, see rank | 11.41% | 9.85% |
Divorced | 5,549 | 15.27%, see rank | 13.47% | 11.60% |
US Census 2000 data
Total population: 75,226
Kendall, FL | % | Florida | U.S. | |
15 Years and Over Total | 60,929 | see rank | 12,946,990 | 221,148,671 |
Males, 15 Years and Over | 27,706 | 100%, see rank | 6,232,987 | 107,027,405 |
Never Married | 7,795 | 28.13%, see rank | 27.32% | 30.26% |
Married | 16,858 | 60.85%, see rank | 59.03% | 58.58% |
Widowed | 475 | 1.71%, see rank | 3.20% | 2.52% |
Divorced | 2,578 | 9.30%, see rank | 10.45% | 8.65% |
Females, 15 Years and Over | 33,223 | 100%, see rank | 6,714,003 | 114,121,266 |
Never Married | 7,906 | 23.80%, see rank | 20.46% | 24.13% |
Married | 17,095 | 51.46%, see rank | 54.55% | 54.60% |
Widowed | 3,252 | 9.79%, see rank | 12.31% | 10.49% |
Divorced | 4,970 | 14.96%, see rank | 12.68% | 10.78% |
* ACS stands for U.S. Census American Community Survey. According to the U.S. Census, if the date is a range, you can interpret the data as an average of the period of time.