64679 Zip Code Historical Education Level Data
ACS 2010-2014 data
Total population: 635
64679 Zip Code | Missouri | U.S. | |
Total 25 Years and Over Population | 433, 100% | 4,028,930 | 209,056,129 |
Less Than High School | 85, 19.63%, see rank | 11.98% | 13.67% |
High School Graduate | 148, 34.18%, see rank | 31.41% | 27.95% |
Some College or Associate Degree | 130, 30.02%, see rank | 29.95% | 29.09% |
Bachelor Degree | 57, 13.16%, see rank | 16.69% | 18.27% |
Master, Doctorate, or Professional Degree | 13, 3.00%, see rank | 9.96% | 11.01% |
USA.com Education Index# | 12.55, see rank | 13.49 | 13.54 |
# Higher USA.com Education Index means more educated population.
ACS 2008-2012 data
Total population: 744
64679 Zip Code | Missouri | U.S. | |
Total 25 Years and Over Population | 426, 100% | 3,973,614 | 204,336,017 |
Less Than High School | 92, 21.60%, see rank | 12.81% | 14.28% |
High School Graduate | 144, 33.80%, see rank | 31.72% | 28.24% |
Some College or Associate Degree | 120, 28.17%, see rank | 29.70% | 28.99% |
Bachelor Degree | 61, 14.32%, see rank | 16.16% | 17.88% |
Master, Doctorate, or Professional Degree | 9, 2.11%, see rank | 9.61% | 10.61% |
USA.com Education Index# | 12.42, see rank | 13.40 | 13.47 |
# Higher USA.com Education Index means more educated population.
US Census 2000 data
Total population: 787
64679 Zip Code | Missouri | U.S. | |
Total 25 Years and Over Population | 540, 100% | 3,634,906 | 182,211,639 |
Less Than High School | 114, 21.11%, see rank | 18.68% | 19.60% |
High School Graduate | 233, 43.15%, see rank | 32.73% | 28.63% |
Some College or Associate Degree | 147, 27.22%, see rank | 27.01% | 27.37% |
Bachelor Degree | 36, 6.67%, see rank | 13.97% | 15.54% |
Master, Doctorate, or Professional Degree | 10, 1.85%, see rank | 7.61% | 8.86% |
USA.com Education Index# | 12.10, see rank | 12.88 | 13.01 |
# Higher USA.com Education Index means more educated population.
* ACS stands for U.S. Census American Community Survey. According to the U.S. Census, if the date is a range, you can interpret the data as an average of the period of time.