USA.com / Vermont / Orleans County / Craftsbury Common, VT / 05827 / Population and Races / Historical School Enrollment Data
05827 Zip Code Historical School Enrollment Data
ACS 2010-2014 data
Total population: 358
05827 Zip Code | Vermont | U.S. | |||||
Total | Public | Private | Public | Private | Public | Private | |
Nursery School, Preschool, Kindergarten | 7 | 28.57% | 71.43% | 73.30% | 26.70% | 71.30% | 28.70% |
Elementary School (Grades 1-8) | 22 | 81.82%, see rank | 18.18%, see rank | 91.08% | 8.92% | 89.86% | 10.14% |
High School (Grades 9-12) | 13 | 100.00%, see rank | 0.00%, see rank | 89.56% | 10.44% | 90.60% | 9.40% |
College | 53 | 39.62%, see rank | 60.38%, see rank | 65.08% | 34.92% | 78.37% | 21.63% |
ACS 2008-2012 data
Total population: 286
05827 Zip Code | Vermont | U.S. | |||||
Total | Public | Private | Public | Private | Public | Private | |
Nursery School, Preschool, Kindergarten | 3 | 100.00% | 0.00% | 70.90% | 29.10% | 70.05% | 29.95% |
Elementary School (Grades 1-8) | 9 | 100.00%, see rank | 0.00%, see rank | 91.46% | 8.54% | 89.62% | 10.38% |
High School (Grades 9-12) | 7 | 100.00%, see rank | 0.00%, see rank | 88.49% | 11.51% | 90.52% | 9.48% |
College | 45 | 57.78%, see rank | 42.22%, see rank | 65.21% | 34.79% | 77.79% | 22.21% |
US Census 2000 data
Total population: 328
05827 Zip Code | Vermont | U.S. | |||||
Total | Public | Private | Public | Private | Public | Private | |
Nursery School, Preschool, Kindergarten | 13 | 100.00% | 0.00% | 71.08% | 28.92% | 68.05% | 31.95% |
Elementary School (Grades 1-8) | 27 | 100.00%, see rank | 0.00%, see rank | 92.78% | 7.22% | 89.11% | 10.89% |
High School (Grades 9-12) | 22 | 86.36%, see rank | 13.64%, see rank | 89.62% | 10.38% | 90.65% | 9.35% |
College | 31 | 54.84%, see rank | 45.16%, see rank | 62.32% | 37.68% | 77.59% | 22.41% |
Graduate School | 3 | 100.00%, see rank | 0.00%, see rank | 51.52% | 48.48% | 60.73% | 39.27% |
* ACS stands for U.S. Census American Community Survey. According to the U.S. Census, if the date is a range, you can interpret the data as an average of the period of time.